Ok my question is I have a php function that's getting info from the mysql database
but at the end it would start a javascript function, is it possible to do it like
echo '<div style="none" onLoad="java script:function name"></div>';
php & javascript function
Started by Nightscream, Jan 21 2007 07:25 AM
7 replies to this topic
#1
Posted 21 January 2007 - 07:25 AM
#2
Posted 21 January 2007 - 02:21 PM
mmh but it has to do a php function first and at the end of the php function it has to execute the javascript function
#3
Posted 21 January 2007 - 03:24 PM
yeah but it only have to do the javascript function when the php function blah is over
so if it's not over it should do the javascript function
so if it's not over it should do the javascript function
#4
Posted 21 January 2007 - 03:53 PM
So would the php be getting a variable for the Javascript to use?
#5
Posted 21 January 2007 - 07:48 PM
so My php file gets some data from the mysql database, file urls and then it puts the variable into
<div style="none">$variable</div>
then javascript function reads it and update a drop down box with the files, cause i have 2 dropdown boxes and if something changes in the first one the second one has to be updated with the right values.
I don't know ajax so i have to find another way
<div style="none">$variable</div>
then javascript function reads it and update a drop down box with the files, cause i have 2 dropdown boxes and if something changes in the first one the second one has to be updated with the right values.
I don't know ajax so i have to find another way
#6
Posted 22 January 2007 - 03:27 PM
ok this is my code
and it makes the comic drop down menu with the rows that is found in the database,
2nd it should execute Get_Pages() and at the end of that function it should start executing
the javascript function GetPages(), the comic drop down works but that's all, no drop down menu update or anything
i think the first error is the onclick event on echo '<option onclick="Get_Pages()">Chapter '.$i.'</option>';
cause it doesn't execute the get_pages() function
I hope you get it now
Bump
and it makes the comic drop down menu with the rows that is found in the database,
2nd it should execute Get_Pages() and at the end of that function it should start executing
the javascript function GetPages(), the comic drop down works but that's all, no drop down menu update or anything
i think the first error is the onclick event on echo '<option onclick="Get_Pages()">Chapter '.$i.'</option>';
cause it doesn't execute the get_pages() function
I hope you get it now
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>Untitled Document</title>
<?php
$hostname = "";
$username = "";
$password = "";
$database = "";
$connect = mysql_connect($hostname, $username, $password);
mysql_select_db($database);
/* --------------------------------------------------------- */
$ComicName = null;
function GetComicName() {
$ComicName = $_GET['Chapter'];
echo $ComicName;
return $ComicName;
}
function Create_Chapter() {
$result = mysql_query("SELECT * FROM Comics");
$num_rows = mysql_num_rows($result);
for($i=1; $i<$num_rows+1; $i++) {
echo '<option onclick="Get_Pages()">Chapter '.$i.'</option>';
}
}
function Get_Pages() {
$result = mysql_query("SELECT ´Pages´ FROM Comics Where ´Name´='$ComicName'");
echo $result;
$num_rows = mysql_num_rows($result);
$files = explode("", $num_rows);
print_r('<div style="display: none;" id="files">'.$files.'</div>');
}
?>
<script type="text/javascript">
function GetPages() {
var filesDiv = getElementById("files")
var files = filesDiv.value
document.print(files)
var num_files = files.lenght
for(var i=0; i<=num_files; i++) {
document.print(files[i])
}
}
</script>
</head>
<body>
<select name="Chapter">
<option selected> </option>
<?php Create_Chapter(); ?>
</select>
<select name="Pages" id="Pages">
<option selected> </option>
</select>
Bump
#7
Posted 28 January 2007 - 02:21 PM
You are obviously not understanding this apparently...
JavaScript cannot access PHP functions because PHP is executed before the script even reaches to the client-side browser.
Here is what you would do.
Since I honestly don't feel like trying to write the whole thing up for you, I'll run you a checklist of what you need to do, as far as I can understand from what you have.
- Grab the comics available [PHP]
- Loop each comic and echo as an option element [PHP]
- Have onchange handler set on the select menu to activate a function [JavaScript]
- This function sends an Ajax request to a PHP script, sending the value of the select menu [JavaScript]
- The PHP queries the database for all pages of the comic is gets from the Ajax call [PHP]
- Loops and echos formatted string with all pages available for that comic (seperated by '|' probably) [PHP]
- JavaScript grabs the string and splits it by that deliminator ('|') [JavaScript]
- Loops and writes each page in whatever format [JavaScript]
Simple searches for 'Ajax' in the JavaScript section will give you plenty of results on how to do this.
JavaScript cannot access PHP functions because PHP is executed before the script even reaches to the client-side browser.
Here is what you would do.
Since I honestly don't feel like trying to write the whole thing up for you, I'll run you a checklist of what you need to do, as far as I can understand from what you have.
- Grab the comics available [PHP]
- Loop each comic and echo as an option element [PHP]
- Have onchange handler set on the select menu to activate a function [JavaScript]
- This function sends an Ajax request to a PHP script, sending the value of the select menu [JavaScript]
- The PHP queries the database for all pages of the comic is gets from the Ajax call [PHP]
- Loops and echos formatted string with all pages available for that comic (seperated by '|' probably) [PHP]
- JavaScript grabs the string and splits it by that deliminator ('|') [JavaScript]
- Loops and writes each page in whatever format [JavaScript]
Simple searches for 'Ajax' in the JavaScript section will give you plenty of results on how to do this.
#8
Posted 28 January 2007 - 04:27 PM
ok ty i'll try this!!!
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