$$_v=($$_c[2]!=''?$$_c[2]:$_c[2])
could someone kind of step me through what's happening here. I would appreciate it.
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Help Understanding PHP Expression
Started by jakevfr, Feb 02 2007 05:05 PM
3 replies to this topic
#1
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Young Padawan
Posted 02 February 2007 - 05:05 PM
I'm trying to work with a PHP script and I've come accross this
could someone kind of step me through what's happening here. I would appreciate it.
could someone kind of step me through what's happening here. I would appreciate it.
#2
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Posted 02 February 2007 - 05:15 PM
its another way of doing an IF statement. I don't get what the deal with the $$ is thou, but here we go:
$$_v = if( $$_c[2] != '' ) { $$_c[2]; } else { $_c[2]; }
Thats how it would be laid out normally with the IF statement.
$$_v = the outcome of the if statement.
If value at position 3 of the array $$_c does not equal nothing, then $$_v gets set to the value at position 2 in the array $_c.
Matt
$$_v = if( $$_c[2] != '' ) { $$_c[2]; } else { $_c[2]; }
Thats how it would be laid out normally with the IF statement.
$$_v = the outcome of the if statement.
If value at position 3 of the array $$_c does not equal nothing, then $$_v gets set to the value at position 2 in the array $_c.
Matt
#3
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Young Padawan
Posted 02 February 2007 - 05:38 PM
Thank you. Now I can finish up my program.
#4
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Posted 03 February 2007 - 03:44 PM
Mr. Matt, on Feb 2 2007, 04:15 PM, said:
I don't get what the deal with the $$ is thou
Variable variables.
http://us3.php.net/m...es.variable.php
Edited by Demonslay, 03 February 2007 - 03:44 PM.
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