1 reply to this topic

[raenef]

Okie so Im trying to setup a url like www.mydomain.com/index.php?id=gallery
and I have that working however if I dont include the ?id=gallery or ?id=anything and just do www.mydomain.com it returns the error
Notice: Undefined index: id in C:\server\www\kattest\index.php on line 2

I know this has been asked many times before in the forums, and I've searched and tried every possible way with similar results.
The Code I Am Using Now:

<?php
$id = $_GET['id'];
switch($id)
{
case "home":
include('assets/content/home.php');

break; case "page":
include('page.php');

break; case "page2":
include('otherpage.php');

break; case "contact":
include('contact.php');

default:
include('assets/content/home.php');
}
?>

Ive even tried this way

<?php
require('header.php');

$page = $_GET['page'];
if (($page == "home") or ($page =="")) {
include('news/news.php');
} else if($page == "projects") {
include('content/projects.html');
} require('footer.php');
?>

Edit: I of course edited this code to suit my need (I know it doesnt match the same navigation as the one before I just hurried to copy and paste)

With similar results saying undefined index page or something of the like.

Since these arent critical errors, I can probably fix them by turning off notices in my php installation (since they're both just notices) But I need to know how to do this (or a fix to the code)

Either way would work, thanks in advance.


Edit: Fixed it, to turn off notices I just added error_reporting(0); to the beginning of the php script.

Edited by raenef, 11 July 2005 - 10:22 PM.

[rc69]

well, fixed or not, your "switch" statement is technically incorrect. While it may work, you should think about updating it to this:

<?php
$id = $_GET['id'];
switch($id)
{
case "home":
include('assets/content/home.php');

break; case "page":
include('page.php');

break; case "page2":
include('otherpage.php');

break; case "contact":
include('contact.php');

break; default:
include('assets/content/home.php');
}
?>